H=3+35x-16x^2

Solution for H=3+35x-16x^2 equation:

=3+35H-16H^2

We move all terms to the left:

-(3+35H-16H^2)=0

We get rid of parentheses

16H^2-35H-3=0

a = 16; b = -35; c = -3;
Δ = b2-4ac
Δ = -352-4·16·(-3)
Δ = 1417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1417}}{2*16}=\frac{35-\sqrt{1417}}{32}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1417}}{2*16}=\frac{35+\sqrt{1417}}{32}
$